the balanced equation for the formation of ammonia is as follows N₂ + 3H₂ ---> 2NH₃ stoichiometry of H₂ to N₂ is 3:1 number of H₂ moles reacted - 2.79 g / 2 g/mol = 1.40 mol if 3 mol of H₂ reacts with 1 mol of N₂ then 1.40 mol of H₂ reacts with - 1.40/3 = 0.467 mol of N₂ mass of N₂ required - 0.467 mol x 28 g/mol = 13.1 g mass of N₂ formed is 13.1 g
