For this case we have the following functions: f (x) = 3x + 1 g (x) = x ^ 2 - 6 Subtracting both functions we have: (f-g) (x) = f (x) - g (x) (f-g) (x) = (3x + 1) - (x ^ 2 - 6) (f-g) (x) = 3x + 1 - x ^ 2 + 6 (f-g) (x) = - x ^ 2 + 3x + 7 Answer: (f-g) (x) = - x ^ 2 + 3x + 7 option B
