Respuesta :
The equation for the reaction is;
CaCO3(s) +2 HCl(aq) = CaCl2(aq) + CO2(s) + H2O(l)
Mass of calcium chloride is 5 ×10^3 kg
Moles of calcium chloride will be; (5× 10^6 g)/ 110.98 g/mol = 4.5 × 10^4 moles
Using the mole ratio; HCl : CaCO3 = 2:1
Thus; the number of moles of HCl will be ; 9.0 ×10^4 moles
The mass of HCl = 9.0 × 10^4 moles ×36.46
= 3.29 × 10^6 kg or 3.29 × 10^3 kg
CaCO3(s) +2 HCl(aq) = CaCl2(aq) + CO2(s) + H2O(l)
Mass of calcium chloride is 5 ×10^3 kg
Moles of calcium chloride will be; (5× 10^6 g)/ 110.98 g/mol = 4.5 × 10^4 moles
Using the mole ratio; HCl : CaCO3 = 2:1
Thus; the number of moles of HCl will be ; 9.0 ×10^4 moles
The mass of HCl = 9.0 × 10^4 moles ×36.46
= 3.29 × 10^6 kg or 3.29 × 10^3 kg
Answer : The correct answer is 1.64 * 10³ Kg.
Given : Mass of CaCl₂ = 5.00 * 10³ Kg
Converting Kg to g using ( 1 Kg = 1000 g)
[tex] Mass of CaCl_2 = 5.00 * 10^3 Kg *\frac{1000 g}{1 Kg } [/tex]
Mass of CaCl₂ = 5.00 * 10⁶ g
Following steps can be done :
Step 1) To write a balanced reaction :
The reaction between Calcium Carbonate and Hydrochloric acid as:
[tex] CaCO_3 + 2 HCl \rightarrow CaCl_2 + CO_2 + H_2O [/tex]
Step 2 ) To find mole of CaCl₂ .
Mass of compound can be used to calculate mole by Mole formula as :
[tex] Mole (mol) = \frac{given mass (g) }{molar mass \frac{g}{mol}} [/tex]
Mass of CaCl₂ = 5 * 10⁶ g Molar mass of CaCl₂ = 110.98[tex] \frac{g}{mol} [/tex]
Plugging values in formula
[tex] Mole = \frac{5*10^6 g}{110.98 \frac{g}{mol}} [/tex]
Mole of CaCl₂ = 4.5 * 10^4 mol
Step 3) To write mole ratio of HCl : CaCl₂
Mole ratio is found from balanced reaction .
Mole of HCl in balanced reaction = 2 mol
Mole of CaCl₂ in balanced reaction = 1 mol
hence mole ratio of HCl : CaCl₂ = 2 : 1
Step 4) To find mole of HCl
Mole of HCl can be calculated using mole of CaCl₂ and mole ratio as :
[tex] Mole of HCl = mole of CaCl_2 * Mole ratio [/tex]
[tex] Mole of HCl = 4.5 * 10^4 mol * \frac{2}{1} [/tex]
Mole of HCl = 9.0 * 10⁴ mol
Step 5) To find mass of HCl
Mass of HCl can be calculates using its mole by Mole formula as:
Molar mass of HCl = 36.5 [tex] \frac{g}{mol} [/tex]
Mole of HCl = 9.0 * 10⁴ mol
Plugging values in Mole formula as:
[tex] 9.0 * 10^4 mol = \frac{mass of HCl }{36.5 \frac{g}{mol}} [/tex]
Multiplying both side by [tex] 36.5 \frac{g}{mol} [/tex]
[tex] 9.0 * 10^4 mol * 36.5 \frac{g}{mol}= \frac{mass of HCl }{36.5 \frac{g}{mol}} * 36.5 \frac{g}{mol} [/tex]
Mass of HCl = 3.285 * 10⁶ g
Step 6) Convert mass of HCl from g to Kg
1 Kg = 1000 g
[tex] Mass of HCl = 3.285 *10^6 g *\frac{1 Kg}{1000 g} [/tex]
Mass of HCl = 3.285 * 10³ Kg
Hence mass of HCl required to produce 5.00 * 10³ Kg of CaCl₂ is 3.285 *10³Kg.
