The slope-point form of a line:
[tex]y-y_1=m(x-x_1)[/tex]
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have (5, 3) and (2, 6).
Substitute:
[tex]m=\dfrac{6-3}{2-5}=\dfrac{3}{-3}=-1[/tex]
[tex]y-3=-1(x-5)\\\\y-3=-x+5\qquad|+3\\\\y=-x+8[/tex]
Answer: y = -x + 8
