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Jessica stretches her arms out 0.6 m from the center of her body while holding a 2 kg mass in each hand. She then spins around on an ice rink at 1.1 m/s.


If she pulls her arms in to 0.15 m, what is her linear speed if the angular momentum remains constant?


Angular momentum = moment of inertia * angular velocity

Moment of inertia = mass * radius^2

Angular velocity = linear speed / radius

Linear speed = distance / time

Respuesta :

As per angular momentum conservation we can say

[tex]L_i = L_f[/tex]

here we know that

[tex]mv_1r_1 = mv_2r_2[/tex]

we know that

[tex]v_1 = 1.1 m/s[/tex]

[tex]r_1 = 0.6 m[/tex]

[tex]v_2 = ?[/tex]

[tex]r_2 = 0.15 m[/tex]

now from above equation

[tex]2(1.1)(0.6) = 2(v_2)(0.15)[/tex]

[tex]v_2 = \frac{(1.1)(0.6)}{0.15}[/tex]

[tex]v_2 = 4.4 m/s[/tex]

so speed is 4.4 m/s

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