Point A is located at (3, 6) and point B is located at (10,−2) .

What are the coordinates of the point that partitions the directed line segment AB⎯⎯⎯⎯⎯ in a 1:3 ratio?



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Respuesta :

Answer:

(4.75, 4)

Step-by-step explanation:

We are to find the coordinates of the point that partitions the directed line segment AB in 1:3 ration.

For this, we will use the following formula:

[tex] x = x_1 + k(x_2 - x_1) [/tex] , [tex] y = y_1 + k(y_2-y_1) [/tex]

where [tex] k [/tex] is the ratio of the first segment to the whole line segment so in this case, it will [tex] \frac{1}{4} [/tex].

So substituting the given values in the above formula to find the coordinates:

[tex] x = 3 + \frac {1}{4} (10-3) = 4.75 [/tex]

[tex] y = 6 + \frac{1}{4} (-2-6) = 4 [/tex]

Therefore, the coordinates of the point that partitions the directed line segment AB in a 1:3 ratio are (4.75, 4).

Answer:

(4.75, 4)

Step-by-step explanation:

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