Answer:
[tex]=\frac{1\pm \sqrt{43}}{6}[/tex]
Step-by-step explanation:
The given equation is 6x² - 2x = 7
We have to solve this equation to get the value of x
6x² - 2x - 7 = 0
Now we apply the quadratic formula in this equation.
[tex]x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}[/tex]
Here b = (-2), a = 6 and c = (-7)
[tex]x=\frac{+2\pm \sqrt{(-2)^{2}-4(6)(-7))}}{2(6)}[/tex]
[tex]=\frac{2\pm \sqrt{4+168}}{12}[/tex]
[tex]=\frac{2+\sqrt{172}}{12}[/tex]
[tex]x=\frac{2\pm \sqrt{4(43)}}{12}[/tex]
[tex]x=\frac{2\pm 2\sqrt{43}}{12}[/tex]
x [tex]=\frac{2(1\pm\sqrt{43} }{12}[/tex]
x [tex]=\frac{1\pm \sqrt{43}}{6}[/tex]
