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A rock is tossed at an initial velocity of 60 m/s at an angle of 10° with the ground. After 0.9 second, how far has the rock traveled horizontally and vertically?

Respuesta :

Step-by-step explanation:

In the x direction:

x = x₀ + v₀ₓ t + ½ at²

x = (0 m) + (60 m/s cos 10°) (0.9 s) + ½ (0 m/s²) (0.9 s)²

x ≈ 53 m

In the y direction:

y = y₀ + v₀ᵧ t + ½ gt²

y = (0 m) + (60 m/s sin 10°) (0.9 s) + ½ (-9.8 m/s²) (0.9 s)²

y ≈ 5.4 m

Answer:

53.2 m horizontally and 5.4 m vertically

Step-by-step explanation: