NEED HELP WITH A MATH QUESTION WITH FINDING A SURFACE AREA OF A SQAURE PYRAMID

ANSWER
[tex]S.A = 125 {in}^{2} [/tex]
EXPLANATION
The total surface area of a square pyramid is the area of the 4 triangular faces plus the area of the square base.
This is given by the formula!
[tex]S.A = 4 \times \frac{1}{2} bh + {l}^{2} [/tex]
From the diagram, the base is 5 inches and the height is 10 inches.
We substitute the values to get:
[tex]S.A = 4 \times \frac{1}{2} \times 5 \times 10 + {5}^{2} [/tex]
This simplifies to;
[tex]S.A = 100 + 25[/tex]
[tex]S.A = 125 {in}^{2} [/tex]