The graph of the given equation is the line that passes through (0,-1) and (3/2,0) and whose slope is m = 2/3 and this can be determined by using the slope-intercept form of the line.
Given :
Equation - [tex](y -1) = \dfrac{2}{3}(x-3)[/tex]
The following steps can be used to draw the graph of the given equation:
Step 1 - Write the given equation.
[tex](y -1) = \dfrac{2}{3}(x-3)[/tex]
Step 2 - Simplify the above equation.
[tex]y = \dfrac{2}{3}x - 2 + 1[/tex]
[tex]y = \dfrac{2}{3}x - 1[/tex]
Step 3 - Draw the graph of (y = x).
Step 4 - Find the y-intercept and the slope of the above equation.
c = -1
[tex]m = \dfrac{2}{3}[/tex]
Step 5 - So, the graph of the given equation is the line that passes through (0,-1) and (3/2,0) and whose slope is m = 2/3.
For more information, refer to the link given below:
https://brainly.com/question/10712002
