Answer:
The distance traveled by the swan is 60.35 meters.
Explanation:
Given that,
A swan accelerate from rest (u = 0) to 6.5 m/s to take off.
Acceleration of the swan, [tex]a=0.35\ m/s^2[/tex]
We need to find the distance Δx it travel before becoming airborne. From the third equation of motion as :
[tex]\Delta x=\dfrac{v^2-u^2}{2a}[/tex]
[tex]\Delta x=\dfrac{(6.5)^2}{2\times 0.35}[/tex]
[tex]\Delta x=60.35\ m[/tex]
So, the distance traveled by the swan is 60.35 meters. Hence, this is the required solution.
