Answer:
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
Step-by-step explanation:
we know that
The speed is equal to divide the distance by the time
Let
x -----> the speed of the wind in miles per hour
y ----> the speed of the jet in still air in miles per hour
we know that
With a tailwind
[tex]y+x=\frac{868}{2}[/tex]
[tex]y+x=434[/tex] ----> equation A
With a headwind
[tex]y-x=\frac{792}{2}[/tex]
[tex]y-x=396[/tex] ----> equation B
solve the system of equations A and B by elimination
Adds equation A and equation B
[tex]y+x=434\\y-x=396\\------\\y+y=434+396\\2y=830\\y=415[/tex]
Find the value of x
[tex]y+x=434[/tex]
[tex]415+x=434[/tex]
[tex]x=434-415[/tex]
[tex]x=19[/tex]
therefore
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
Answer:
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
