Answer:
F= 5.95 N
Explanation:
Forces acting on the body in equilibrium :
W = 9.6 N : in direcction vertical downward
F₁ = 6.9 N : acts from above on the right at an angle of 52° with the horizontal
F : acts from above on the left at an angle of α
x-y components of the force = 6.9 N
F₁x= 6.9 N*cos (52)°= 4.248 N
F₁y= 6.9N*sin (52)°= 5.437 N
Newton's first law for equilibrium
∑Fx=0
F₁x-Fx=0
Fx = F₁x
Fx = 4.248 N
∑Fy=0
F₁y + Fy -W = 0
Fy = W - F₁y
Fy = 9.6 N - 5.437 N
Fy = 4.16 N
Magnitude of the force F
[tex]F=\sqrt{(F_{x})^{2} +(F_{y})^{2} }[/tex]
[tex]F=\sqrt{(4.248)^{2} +( 4.16)^{2} }[/tex]
F= 5.95 N
