Answer : The volume of ammonium chloride at STP is, 445.088 L
Solution : Given,
Moles of ammonium chloride = 19.87 mole
As we know that at STP,
1 mole contains 22.4 L volume of gas
As, 1 mole of ammonium chloride contains 22.4 L volume
So, 19.87 moles of ammonium chloride contains [tex]22.4\times 19.87=445.088L[/tex] volume
Therefore, the volume of ammonium chloride at STP is, 445.088 L