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A ball is dropped from a cliff that is 256 feet high. The height of the ball (in feet) after t seconds is given by the formula h(t) = 256 - 16t^2. How many seconds (to the nearest tenth) will it take for the ball to hit the ground?A. 4096 sec B. 16sec C. 15.5 sec D. 4 sec

Respuesta :

Answer:

t = 4 sec

Explanation:

given,

height of the cliff = 256 ft

equation of height and time

h(t) = 256 - 16 t²

time at which the ball hit the ground = ?

when the ball hit the ground height of the cliff is equal to zero

h(t) = 0                

now,              

0 = 256 - 16 t²      

16 t² = 256          

t² = 16                  

t = 4 sec        

hence, height of the ball will be equal to zero when time is 4 seconds.

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