Answer:
(a) Velocity will be 17.146 m/sec
(b) Volume flow rate will be [tex]66.871\times 10^{-3}m^3/sec[/tex]
Explanation:
We have given height of the dam h = 15 m
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
Effective area [tex]A=3.90\times 10^{-3}m^2[/tex]
(a) From conservation of energy
Potential energy at the top will be equal to kinetic energy at the bottom
So [tex]mgh=\frac{1}{2}mv^2[/tex]
[tex]v=\sqrt{2gh}=\sqrt{2\times 9.8\times 15}=17.146m/sec[/tex]
(b) We have to find the volume flow rate
Volume flow rate is given by
[tex]V=area\times velocity = 3.9\times 10^{-3}\times 17.146=66.871\times 10^{-3}m^3/sec[/tex]
