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Assume that a force acting on an abject is given by F⃗ = a x ihat + b y jhat, where the constants a = 3.0N/m and b = 4.0N/m. Determine the work done on the object by this force as it moves in a straight line from the origin to r⃗ = (10 ihat + 20 jhat) m.

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lcmendozaf

Answer:

W = 950J

Explanation:

From the problem we have these values:

F = [3x,4y]N

ΔX = 10m

ΔY = 20m

[tex]W = \int\limits {F} \, dr[/tex]

[tex]W = \int\limits^{10}_0 {3x} \, dx +\int\limits^{20}_0 {4y} \, dy[/tex]

[tex]W = 150 J+800 J[/tex]

[tex]W = 950 J[/tex]

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