How many calories would be needed to evaporate half of a 300kg puddle of water?
90,000,000 Calories would be needed to evaporate half of a 300kg puddle of water.
Explanation:
On average, 1 liter of water has a mass of 1 kg which requires 540,000 calories or [tex]2.3 \times 10^6[/tex] Joules of energy to get evaporated when the temperature rises to 100 degrees. In the event that the water starts at a temperature T degrees, at that point an extra [tex](100 - T) \times 10^3[/tex] calories would be required to raise.
Since for 300kg of water we need 162000000 calories of energy .
Given:
1 kg = 540,000 calories or [tex]2.3 \times 10^6[/tex]
300Kg = [tex]300 \times 540000[/tex]
[tex]= 162000000[/tex]
If half of the 300kg puddle has evaporate. Then [tex]\frac{162000000}{2}[/tex]
[tex]= 81000000[/tex] calories of energy
So the evaporate value of 300kg puddle of water will be around 90000000 calories.
