66) b) How much hydrazine, in grams, is needed to produce 10.0 mol of nitrogen gas?
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There are 320 grams of hydrazine is needed to produce 10.0 mol of nitrogen gas.
It is an inorganic compound whose Chemical formula is [tex]\rm N_2H_4[/tex]
The molar mass of [tex]\rm N_2H_4[/tex]= 32.0 g/mol
Chemical formula for hydrogen peroxide is [tex]H_2O_2[/tex]
The balanced equation is [tex]\rm N_2H_4 + 2H_2O_2 == > N_2 + 4H_2O[/tex]
10 mol N2 x 1 mol N2H4 / mol N2 x 32.0 g N2H4 / mol = 320 g N2H4
Thus, there are 320 grams of hydrazine is needed to produce 10.0 mol of nitrogen gas.
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