Rahul solved the equation 2(x – ) – 2 left-parenthesis x minus StartFraction 1 Over 8 EndFraction right-parenthesis minus StartFraction 3 Over 5 EndFraction x equals StartFraction 55 Over 4 EndFraction x = 2 left-parenthesis x minus StartFraction 1 Over 8 EndFraction right-parenthesis minus StartFraction 3 Over 5 EndFraction x equals StartFraction 55 Over 4 EndFraction . In which step did he use the addition property of equality?
step 1
step 2
step 3
step 4
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Rahul solved the equation 2x 2 leftparenthesis x minus StartFraction 1 Over 8 EndFraction rightparenthesis minus StartFraction 3 Over 5 EndFraction x equals Sta class=

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Answer:

Step 3

Step-by-step explanation:

got it right

Answer:

C). Step 3

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Step-by-step explanation: