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The diagram below depicts a wire, xy, moving through a uniform magnetic field toward point A. The length of the wire is 0.20 meter and the magnetic field strength is 0.50 newton per ampere-meter. The wire moves uniformly at 1.0 meter per second.

What is the magnitude of the induced voltage in wire xy?

Respuesta :

skyluke89

Induced voltage: 0.10 V

Explanation:

For a conducting wire moving perpendicular to a magnetic field, the magnitude of the induced emf (voltage) in the wire is given by

[tex]\epsilon=BLv[/tex]

where

B is the magnitude of the magnetic field

L is the length of the wire

v is the speed of the wire

In this problem, we have

B = 0.50 T is the strength of the magnetic field

v = 1.0 m/s is the speed of the wire

L = 0.20 m is the length

Substituting, we find the induced voltage:

[tex]\epsilon=(0.50)(0.20)(1.0)=0.10 V[/tex]

Learn more about magnetic fields:

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