Answer:
The overall heat transfer is 200 kJ
Explanation:
Q = ∆U + W
Q is quantity of heat transfer
∆U is change in internal energy
W is work done
Assuming the process is an isometric process (constant volume) in which work done is 0
Therefore, Q = ∆U + 0
Q = ∆U
∆U = U2 - U1 = 200 - 100 = 100 kJ/kg
Total mass of gas = 2 kg
∆U = 100 kJ/kg × 2kg = 200 kJ
Q = 200 kJ
