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Which of the following could be the equation for a parabola that opens to the
left with vertex (5, -12)?
O
A. x = (y-5)2 - 12
O
B. y = (x+12)2 +5
O
C. y = (x-5)2 - 12
O D. x=-(y+12)2 +5

Respuesta :

frika

Answer:

D. [tex]x=-(y+12)^2+5[/tex]

Step-by-step explanation:

A parabola that opens to the left has the equation

[tex](y-y_0)^2=-2p(x-x_0),[/tex]

where [tex](x_0,y_0)[/tex] is the vertex.

If the vertex of the parabola is at the point (5,-12), then its equation is

[tex](y-(-12))^2=-2p(x-5)\\ \\(y+12)^2=-2p(x-5)[/tex]

When [tex]p=\frac{1}{2},[/tex] the equation is

[tex](y+12)^2=-(x-5)\\ \\(y+12)^2=-x+5\\ \\x=-(y+12)^2+5[/tex]

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