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Oxygen gas is at a temperature of 40 Celsius when it occupies a volume of 2.3 L. To what temperature should it be raised to occupy a volume of 6.5 L?

Respuesta :

Answer:

The temperature should be 885K.

Explanation:

In this case we use Charles's Law according to which the volume and temperature of a certain amount of gas are related, keeping the pressure constant. We convert the unit of temperature from Celsius to Kelvin: 0 = 273K -> 40 ° C = 40 + 273 = 313K

V1 / T1 = V2 / T2

2,3L/313K= 6,5L/T2

T2=6,5L/(2,3L/313K)=884, 56K

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