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A sled is on an icy (frictionless) slope that is 30° above the horizontal. When a 40-N force, parallel to the incline and directed up the incline, is applied to the sled, the acceleration of the sled is 2.0 m/s 2, down the incline.. The mass of the sled is:

Respuesta :

Answer: 5.8kg

Explanation:

F - mg sinΦ = ma

Given that

M=?

g= 9.8

Φ= 30

a= 2

F= 40 then

40 - 9.8 * m * sin 30 = 2 * m

40 = 2 * m + 9.8 * m * sin 30

40 = (2 + 9.8 * sin 30) m

m = 40 / (2 + 9.8 * 0.5)

m = 40 / (2 + 4.9)

m = 40 / 6.9

m = 5.797kg

m = 5.8kg

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