Answer : The correct option is, at the corners of a tetrahedron.
Explanation :
Formula used :
[tex]\text{Number of electron pair}=\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
Now we have to determine the hybridization of the given molecule.
The given molecule is, [tex]CH_4[/tex]
[tex]\text{Number of electrons}=\frac{1}{2}\times [4+4]=4[/tex]
The number of electron pair are 4 that means the hybridization will be [tex]sp^3[/tex] and the electronic geometry of the molecule will be tetrahedral and the bond angle will be, [tex]109.5^o[/tex].
Hence, the correct option is, at the corners of a tetrahedron.