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A tiny sample of an aqueous solution of two substances R and P is sketched below as if it was under an imaginary microscope so powerful that molecules could be seen. (The water molecules are not shown.) R and P can interconvert. That is, R can turn into P, and P can turn back into R 2 The equilibrium constant K for this equilibrium is. Predict the number of R and P molecules in this sample when the interconversion reaches equilibrium. a number of R molecules: D number of P molecules:

Respuesta :

Answer:

R = 6, P = 6

Explanation:

Answer

Number of R molecules = 6

Number of P molecules = 6

Explanation

R(aq) <-------> P(aq)

K = [P]/[R]

at equillibrium

[ P ] = 10+x

[R] = 2-x

10 + x /(2-x) = 1

10 + x = 2- x

2x = -8

x = -4

Therefore,

[ R] = 2 - ( -4) = 6

[ P ] = 10 + ( -4) = 6

lhmarianateixeira

In this exercise we have to use the knowledge of solution to calculate the number of molecules in this way, so we can say that:

  • R = 6
  • P = 6

So from the data provided by the text, we can say that:

  • Number of R molecules = 6
  • Number of P molecules = 6

Knowing that the reaction is given as:

[tex]R_{(aq)} \rightarrow P_{(aq)}\\ K = [P]/[R][/tex]

The equilibrium of this reaction can be described as follows:

[tex][ P ] = 10+x\\ (R) = 2-x\\ 10 + x /(2-x) = 1\\ 10 + x = 2- x\\ 2x = -8\\ x = -4[/tex]

Then substituting the value of x in each of the equations we find that:

[tex][ R] = 2 - ( -4) = 6 [ P ] = 10 + ( -4) = 6[/tex]

See more about solution at brainly.com/question/7932885

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