Answer:
C. 427, 518, 000
Step-by-step explanation:
-This is a permutation problem.
-A recognition of of permutation of six from a group of 30.
-Hence, the different number of ways is calculated as:
[tex]Ways=_nP_x\\\\=_{30}P_6\\\\=427518000[/tex]
The students can be arranged in 427, 518, 000 ways