Ten times (10 x) the sum (+) of half a number ([tex] \frac{n}{2} [/tex]) and 6 (6) is 8 (=8)
10([tex] \frac{n}{2} [/tex] + 6) = 8 Use the Distributive Property
[tex] \frac{10n}{2} [/tex] + 60 = 8 Simplify the fraction
5n + 60 = 8 Subtract 60 from both sides
5n = -52 Divide both sides by 5
n = -10[tex] \frac{2}{5} [/tex]
