Which of the following compounds provides the most solute particles when
completely dissociated in water?
a) NH4 because it dissociates into five ions.
Ob) MgCl2 because the mass of the particles is greater.
Oc) NaCl because the mass of the formula unit is the smallest.
d) Na3P because it dissociates into four ions.

Respuesta :

Answer:

Na3P because it dissociates into four ions.

Explanation:

Let us take a look at the number of particles formed when Na3P dissolves in water.

Na3P(s) -------> 3Na^+(aq) + P^3- (four ions)

When an ionic solid dissolves in water, solute particles interact with the solvent and dissolve. The number of solute particles in the system depends on the number of ions present in the ionic solid. The more the ions present in the ionic solid, the greater the number of solute particles in the solution.

Of all the substances listed in the options for this question, only Na3P forms four particles in solution. Hence Na3P provides the most number of solute particles in solution.

The compound that provides more solute particles has been  [tex]\rm Na_3P[/tex]  as it has been constituted of four atoms. Thus, option D is correct.

The dissociation of compounds in the solution results in the formation of associated ions. The ions have been dissociated with respect to the formed ions of the compound.

Dissociation of compounds in water

The compound with more number of atoms has been resulted in more number of dissociated particles in the solution. Thus, [tex]\rm Na_3P[/tex] has been constituted of four atoms and results in maximum solute particles. Thus, option D is correct.

For more information about dissociation in water, refer to the link:

https://brainly.com/question/12911351