Answer:
The value of the test statistic [tex]z = -0.6606[/tex]
Step-by-step explanation:
From the question we are told that
The high dropout rate is [tex]\mu = 6.1[/tex]% [tex]= 0.061[/tex]
The sample size is [tex]n = 1000[/tex]
The number of dropouts [tex]x = 56[/tex]
The probability of having a dropout in 1000 people [tex]\= x = \frac{56}{1000} = 0.056[/tex]
Now setting up Test Hypothesis
Null [tex]H_o : p = 0.061[/tex]
Alternative [tex]H_a : p < 0.061[/tex]
The Test statistics is mathematically represented as
[tex]z = \frac{\= x - p}{\sqrt{\frac{p(1 -p)}{n} } }[/tex]
substituting values
[tex]z = \frac{0.056 - 0.061}{\sqrt{\frac{0.061(1 -0.061)}{1000} } }[/tex]
[tex]z = -0.6606[/tex]
