Answer: B. 448.0 moles
Explanation:
The balanced chemical equation is :
[tex]2NBr_3+3NaOH\rightarrow N_2+3NaBr+3HOBr[/tex]
According to stoichiometry :
3 moles of [tex]NaOH[/tex] produce = 1 mole of [tex]N_2[/tex]
Thus 48.00 moles of [tex]NaOH[/tex] will produce =[tex]\frac{1}{3}\times 48.00=16.00moles[/tex] of [tex]N_2[/tex]
Mass of [tex]N_2=moles\times {\text {Molar mass}}=16.00moles\times 28g/mol=448.0g[/tex]
Thus 448.0 g of [tex]N_2[/tex] will be produced from 48.00 moles of NaOH.
