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Find the common ratio for the geometric sequence for which [tex]a_1[/tex]=3 and [tex]a_5[/tex]=48. A. -3 B. -2 C. 3 D. 2

Respuesta :

Sandro0017

Answer:

An= A1 * r^n-1

A5= 3 * r^5-1

48= 3*r^4

48÷3=r^4

16=r^4

r=

[tex] \sqrt[4]{16} [/tex]

r=2

The answer is D. 2

Espero que te sirva

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