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The combustion of octane (C8H18) is represented by the following equation:

2C8H18 + 25O2 ---> 16CO2 + 18H20

How many grams of carbon dioxide (CO2) are formed from 0.929 g of octane?

Respuesta :

Willchemistry
Molar mass :

C8H18 => 114.23g/mol
CO2 => 44.01 g/mol

2 C8H18 + 25 O2 ---> 16 CO2 + 18 H2O

2 x 114.23 g -------------- 16 x 44.01 g
0.929 g ------------------- ( mass of CO2)

mass of CO2 = 0.929 x 16 x 44.01 / 2 x 114.23

mass of CO2 = 654.16464 / 228.46

= 2.863 g of CO2

hope this helps!

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