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You have 150 g of water (m). The specific heat of the water is 4.184 g/jC (c) . You heat the water and raise the temperature by 1 degree. How much heat did the water absorb?

Respuesta :

Answer:

627.6J

Explanation:

q=mcΔT

where:

q = heat energy (J)

m = mass (g)

c = specific heat (g/j*C)

Δt = change in temperature (C/K)

q= (150)(4.184)(1) = 627.6

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