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11. You have $200 and wish to buy a computer. You find an investment that increases
by 0.6% each month, and you put your $200 into the account. When will the
account enable you to purchase a computer costing $500?

Respuesta :

Answer:

I’m not a hundred percent it’s correct

Step-by-step explanation:

I used the online book to get the answer.

Hope this helps

Ver imagen roseangel65

Using an exponential equation, it is found that the account will enable the person to purchase the computer after 153 months.

An exponential equation of increase is modeled by:

[tex]A(n) = A(0)(1 + r)^n[/tex]

In which

  • A(0) is the initial value.
  • r is the rate of increase, as a decimal.

In this problem:

  • $200 put into the account, thus [tex]A(0) = 200[/tex].
  • Increases 0.6% each month, thus [tex]r = 0.006[/tex].

Then:

[tex]A(n) = A(0)(1 + r)^n[/tex]

[tex]A(n) = 200(1 + 0.006)^n[/tex]

[tex]A(n) = 200(1.006)^n[/tex]

You need $500 to purchase the computer, then:

[tex]A(n) = 200(1.006)^n[/tex]

[tex]500 = 200(1.006)^n[/tex]

[tex](1.006)^n = \frac{500}{200}[/tex]

[tex](1.006)^n = 2.5[/tex]

[tex]\log{(1.006)^n} = \log{2.5}[/tex]

[tex]n\log{1.006} = \log{2.5}[/tex]

[tex]n = \frac{\log{2.5}}{\log{1.006}}[/tex]

[tex]n = 153[/tex]

The account will enable you to purchase a computer after 153 months.

A similar problem is given at https://brainly.com/question/14773454

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