need a little help with this problem

Answer:
Step-by-step explanation:
Rate (slope) of miles per gallon of gas: m = [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]
(0, 0)
(2, 50)
[tex]m_{carA}[/tex] = 25 mi/gal.
(0, 0)
(3, 60)
[tex]m_{carB}[/tex] = 20 mi/gal.
Car B use less gasoline.