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[tex]y = {x}^{2} - x - 20[/tex]
[tex]y = (x - 5)(x + 4)[/tex]
To find the zeroes , Just need to put 0 instead of y .
[tex]0 = (x - 5)(x + 4)[/tex]
[tex](x - 5)(x + 4) = 0[/tex]
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Hint :
[tex]a \times b = 0[/tex]
[tex]a = 0 \: \: \: or \: \: \: b = 0[/tex]
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[tex]x - 5 = 0[/tex]
Add sides 5
[tex]x - 5 + 5 = 0 + 5[/tex]
[tex]x = 5[/tex]
Or
[tex]x + 4 = 0[/tex]
Subtract sides 4
[tex]x + 4 - 4 = 0 - 4[/tex]
[tex]x = - 4[/tex]
Thus the zeroes are :
( - 4 , 0 ) and ( 5 , 0 ) .
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