Following are the solution to the given points:
In point a:
When 95% are confidence interval:
[tex]=( \mu_{20-39} - \mu_{60})+(-z_{0.025})((0.09)^2+(0.11)^2)^{0.5} \\\\= (65.9-64.3)+(-1.96) \times 0.14213\\\\=(1.3214, 1.8786)[/tex]
In point b:
[tex]H_0: \mu_1 - \mu_2 =1\\\\ H_a: \mu_1 - \mu_2 > 1[/tex]
In the Z test statistic:
[tex]= \frac{((65.9-64.3)-1)}{((0.09)^2+(0.11)^2)^{0.5}} \\\\= 4.22 \\\\\to p= 0.000012[/tex]
In point c:
The rejection value of the null hypothesis as [tex]p< 0.001[/tex]
In point d:
[tex]H_0: \mu_2 -\mu_1 = 1 \\\\H_a: \mu_2 - \mu_1 > 1[/tex]
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brainly.com/question/16162795