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You dissolved a small amount of your product in about 5 mL of distilled water in a test tube. You then added about 1 mL of 6M HCl solution and finally you heated the final solution. What precipitate formed in the test tube?

Respuesta :

Answer:

Sulfur

Explanation:

The reaction of the following question is as follows:

Na₂S₂O₃ (aq) + 2HCl(aq) --------------⇒2NaCl (aq) + H₂O(l) + SO₂(aq) + S (s)

Precipitate is sulfur.