Answer:
The weight of the water is 37.14 N.
Explanation:
Given;
density of water, ρ = 62.4 lbm/ft³
volume of water, V = 1 gallon = 0.1338 ft³
The mass of the water is calculated as;
m = ρV
[tex]m = 62.4 \ \frac{lbm}{ft^3} \ \times \ 0.1338 \ ft^3\\\\m = 8.349 \ lbm[/tex]
1 lbm = 0.454 kg
8.349 lbm = ?
= 3.79 kg
The weight of the water is calculated as;
W = mg
where;
g is acceleration due to gravity = 9.8 m/s²
W = (3.79)(9.8)
W = 37.14 N.
Therefore, the weight of the water is 37.14 N.
