Respuesta :

Answer:

[tex] 3j^7 [/tex]

Step-by-step explanation:

[tex] \dfrac{-6j^{-8}}{-2(j^{-3})^5} = [/tex]

[tex] = \dfrac{-6j^{-8}}{-2j^{-15}} [/tex]

[tex] = 3j^{-8 - (-15)} [/tex]

[tex] = 3j^7 [/tex]