Answer:
[tex]V_2=12.1L[/tex]
Explanation:
Hello!
In this case, according to the given data of volume, pressure and temperature, it is possible to infer this problem can be solved via the combined gas law:
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
Thus, regarding the question, we evidence we need V2, but first we make sure the temperatures are in Kelvins:
[tex]T_1=20+273=293K\\\\T_2=-40+273=233K[/tex]
Then, we obtain:
[tex]V_2=\frac{P_1V_1T_2}{T_1P_2}\\\\V_2=\frac{0.987atm*8.50L*233K}{293K*0.550atm}\\\\V_2=12.1L[/tex]
Best regards!
