The diagram and data below represent gas and the conditions of pressure, volume, and temperature of the gas in a rigid cylinder with a moveable piston. Determine the volume of the gas in the cylinder at STP.

The diagram and data below represent gas and the conditions of pressure volume and temperature of the gas in a rigid cylinder with a moveable piston Determine t class=

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Answer:

2.3 L

Explanation:

when you have this eqaution you use P1V1T2=P2V2T1.

since you are looking for volume of gas cylinder that means you are looking for V2.

so you have your given P= 1.0 atm, V=2.5L, T=298K.

They ask you to use STP or standard pressure and temperature.

STP P= 1atm, STP T=273 K

so you are looking for V2 meaning you are going to get V alone so your new equation is P1*V1*TS/ P2* T1= V2

so you now substitue so its now 1*273*2.5/ 1* 298= V

682.5/ 298= V

Lastly V= 2.2902 and you round to tenths so now you have

V= 2.3 L

The volume of the gas in the cylinder at STP is 2.3 L

Data obtained from the question

  • Initial volume (V₁) = 2.5 L
  • Initial pressure (P₁) = 1 atm
  • Initial temperature (T₁) = 298 K
  • Final temperature (T₂) = STP = 273 K
  • Final pressure (P₂) = STP = 1 atm
  • Final volume (V₂) =?

Since the pressure is constant, we shall determine the final volume of the gas by using the Charles' law equation as shown below:

V₁ / T₁ = V₂ / T₂

2.5 / 298 = V₂ / 273

Cross multiply

298 × V₂ = 2.5 × 273

298 × V₂ = 682.5

Divide both side by 298

V₂ = 682.5 / 298

V₂ = 2.3 L

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