Let the function P represent the population P(d), in thousands, of a colony of insect
d days after first being measured. A model for P is P(d) = 10. (1.08)". ​

Respuesta :

Answer:

(c) and (e) are true

Step-by-step explanation:

Given

[tex]P(d) = 10. (1.08)^d[/tex]

See attachment for complete question

Required

Which of the options is true

(a) 1080 insects on day 1

This implies that d = 1

So, we have:

[tex]P(1) = 10* (1.08)^1[/tex]

[tex]P(1) = 10* 1.08[/tex]

[tex]P(1) = 10.8[/tex]

(a) is incorrect because [tex]P(1) \ne 1080[/tex]

(b) 10800 insects after a week

This implies that [tex]d = 7[/tex]

So, we have:

[tex]P(7) = 10* (1.08)^7[/tex]

[tex]P(7) = 10* 1.71382426878[/tex]

[tex]P(7) = 17.14[/tex]

(b) is incorrect because [tex]P(7) \ne 10800[/tex]

(c): Growth factor per day is 1.08

An exponential factor is represented as:

[tex]y = ab^x[/tex]

Where

b is the growth factor

By comparison:

[tex]b = 1.08[/tex]

Hence, (c) option is true

(d): Growth factor per week is 1.08*7

In (c), we have:

[tex]b = 1.08[/tex] as the daily growth factor

So, the growth factor for n days is:

[tex]Factor = 1.08^n[/tex]

Substitute 7 for n i.e. 7 days

[tex]Factor = 1.08^7[/tex]

So, the growth factor for 7 days is: [tex]1.08^7[/tex] not [tex]1.08*7[/tex]

Hence, (d) option is true

(e): Growth factor per week is 1.08*7

In (c), we have:

[tex]b = 1.08[/tex] as the daily growth factor

For hourly rate, we have:

[tex]Factor = 1.08^\frac{1}{24}[/tex]

Hence, (e) option is true

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