240 g of water (specific heat = 4.186 J/g°C, initial temperature = 20°C) is mixed with an
unknown mass of iron (specific heat = 0.444 J/gºC, initial temperature 500°C). When
equilibrium is reached, the system has a temperature of 42°С. Find the mass of iron.

Respuesta :

The answer for this would be 69.6

240 g of water (specific heat = 4.186 J/g°C, initial temperature = 20°C) is mixed with an unknown mass of iron (specific heat = 0.444 J/gºC, initial temperature 500°C). When equilibrium is reached,The answer for this would be 69.6

 

How do you find final temperature with specific heat?

You use q = mcΔT, but you assume aluminum = water and crack for This the final temperature.

We need to look up heat values (c) for aluminum and h20. This will uses 0.901 for aluminum and 4.18 use water

: (10)(130 - T)(0.901) = (200.0)(T - 25 (6)

Hence, The answer for this would be 69.6.  

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