Answer:
[tex]sin x=-\frac{5}{13}[/tex]
Step-by-step explanation:
From the question we are told that:
Radius [tex]r=13[/tex]
Co-ordinate of x axis at C [tex]x'=12[/tex]
Let
x' represent the x axis
y' represent the y axis
Since the intercept across the radius has values on the x' and y' axis
Therefore
Generally the Trigonometric equation for cos x is mathematically given by
[tex]cos x=\frac{x'_c}{r}[/tex]
[tex]cos x=\frac{12}{13}[/tex]
Generally the Trigonometric equation for sin x is mathematically given by
[tex]sin x=\sqrt{1-cos^2x}[/tex]
[tex]sin x=\sqrt{1-(\frac{12}{13})^2}[/tex]
[tex]sin x=\frac{5}{13}[/tex]
Since x is in the IV quadrant sin x is negative
[tex]sin x=-\frac{5}{13}[/tex]
