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On a standardized exam, the scores are normally distributed with a mean of 27 and a standard deviation of 4. Find the z-score of a person who scored 17 on the exam.

Respuesta :

Answer:

The answer is "-2.5"

Step-by-step explanation:

Given:

[tex]\mu=27\\\\\sigma=4\\\\x=17\\\\z = \frac{(x-\mu)}{\sigma} \\\\[/tex]

   [tex]= \frac{(17-27)}{4}\\\\= \frac{-10}{4}\\\\=-2.5[/tex]

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