Respuesta :

DimplegirlPayal

Velocity of a particle varies with its displacement as v = ( √(9 ... Velocity of a particle varies with its displacement as v = ( √(9 - x^2) ) m/sFind the magnitude of maximum acceleration of the particle.

spectrojamz

Answer:

Don't know if you meant to write 3t²i - 2tj

If so

a=dv/dt = 6ti - 2j

at t=1sec

a = 6(1)I - 2j

a=6i - 2j

Magnitude of a = √6²+(-2)²

a= 2√10ms-²

or 6.32ms-².