Respuesta :

I am assuming A is base 5 based on the ve

a. 1*5^3 + 3*5^2 + 1*5^1+ 2*5^0
125+75+5+2

a = 207

b. 2+4+16+32+128+256

b = 438

(please note that a binary number having 9 digits is highly unusual. most are normally 8 which makes up a bit)